A car traveling at 11.6 meters per second crashes into a barrier and stops in 0.287 meters. How many times the weight of the child is this force? Answer must be in 3 significant digits.

A car traveling at 116 meters per second crashes into a barrier and stops in 0287 meters How many times the weight of the child is this force Answer must be in class=

Respuesta :

The weight of child can be given as,

[tex]w=mg[/tex]

Substitute the known values,

[tex]\begin{gathered} w=(21.2kg)(9.8m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =207.76\text{ N} \end{gathered}[/tex]

Divide the value of force with the weight.

[tex]\begin{gathered} \frac{F}{w}=\frac{4970\text{ N}}{207.76\text{ N}} \\ =23.9 \end{gathered}[/tex]

Thus, the force is 23.9 times the weight of child.