Given data:
The given equationn of the circle is (x + 1)^2 + (y - 5)^2 = 16.
The standard equation of the circle is,
[tex](x-a)^2+(y-b)^2=r^2[/tex]The given equation can eb written as,
[tex](x-(-1))^2+(y-5)^2=4^2[/tex]Compare the above equation with standard equation.
[tex]\begin{gathered} a=-1 \\ b=5 \\ c=4 \end{gathered}[/tex]Thus, the coordinate of centre is (-1, 5) and radius is 4.
