EXPLANATION;
Given;
We are given the two numbers,
[tex]\frac{2}{25}\text{ }and\text{ }\frac{1}{20}[/tex]
Required;
We are required to arrange them in order and the solution is as follows;
[tex]\begin{gathered} \frac{2}{25}=\frac{4}{4}\times\frac{2}{25} \\ \\ \frac{2}{25}=\frac{8}{100} \end{gathered}[/tex][tex]\frac{1}{20}\times\frac{5}{5}=\frac{5}{100}[/tex]
As we can see, the fractions have been replaced with equivalent and these are;
[tex]\frac{2}{25}(\frac{8}{100})>\frac{1}{20}(\frac{5}{100})[/tex]
As we can see, eight out of 100 is greater than 5 out of 100. Therefore;
ANSWER:
[tex]\frac{2}{25}>\frac{1}{20}[/tex]
