Respuesta :

[tex]\begin{gathered} \text{As we know,} \\ \angle CAF=\angle GAE=x-13 \\ \angle DAG=\angle BAF=x-9 \\ \angle DAC=2x+6 \\ So, \\ \angle CAF+\angle DAG+\angle DAC=180 \\ x-13+x-9+2x+6180 \\ 4x-16=180 \\ 4x=180-16 \\ x=41^{\circ} \end{gathered}[/tex]