You can afford a $1200 per month mortgage payment. You've found a 30 year loan at 7% interest.a) How big of a loan can you afford?$b) How much total money will you pay the loan company?c) How much of that money is interest?$

Respuesta :

The rule of the loan is

[tex]P=\frac{L(\frac{r}{n})}{\lbrack1-(1+\frac{r}{n})^{-nt}\rbrack}[/tex]

P is the monthly payment

L is the loan amount

r is the rate in decimal

n is the number of periods per year

t is the time

Since you afford $1200 per month, then

P = 1200

Since the loan interest is 7%, then

r = 7/100 = 0.07

n = 12

Since the time is 30 years, then

t = 30

Substitute them in the rule above to find L

a)

[tex]\begin{gathered} 1200=\frac{L(\frac{0.07}{12})}{\lbrack1-(1+\frac{0.07}{12})^{-12(30)}\rbrack} \\ 1200\lbrack1-(\frac{1207}{1200})^{-360}\rbrack=L(\frac{0.07}{12}) \\ \frac{1200\lbrack1-(\frac{1207}{1200})^{-360}\rbrack}{\frac{0.07}{12}}=L \\ 180369.0815=L \end{gathered}[/tex]

The amount of the loan is $180 369.0815

b)

You can find the total money you will pay the loan company, multiply P by n by t.

[tex]\begin{gathered} \text{Total}=1200\times12\times30 \\ \text{Total}=432000 \end{gathered}[/tex]

You will pay a total amount of $432 000

c)

The amount of interest is the difference between the total payment and the amount of the loan

[tex]\begin{gathered} I=T-L \\ I=432000-180369.0815 \\ I=251630.9185 \end{gathered}[/tex]

The interest is $251 630.9185