Step 1
Given;
[tex]\begin{gathered} -2x+3y=-3---(1) \\ x+y=4----(2) \end{gathered}[/tex]Required; To solve the system of equations
Step 2
Find the value of x from equation 2
[tex]\begin{gathered} x+y=4 \\ x=4-y \end{gathered}[/tex]Step 3
Substitute for x in equation 1
[tex]\begin{gathered} -2(4-y)+3y=-3 \\ -8+2y+3y=-3 \\ 5y=-3+8 \\ 5y=5 \\ \frac{5y}{5}=\frac{5}{5} \\ y=1 \end{gathered}[/tex]Step 4
Find the value of x using equation 2
[tex]\begin{gathered} x+y=4 \\ x+1=4 \\ x=4-1 \\ x=3 \end{gathered}[/tex]Hence the solution to the system of equations in (x,y) = (3,1) where x=3 and y=1
