Step 1
Given; Find the equation of the line passing through the point (8, -4) and slope -4.
Step 2
The standard equation of a line in slope-intercept form is;
[tex]\begin{gathered} y=mx+c \\ m=slope=-4 \\ c=y-intercept \end{gathered}[/tex]Thus the equation will look like;
[tex]\begin{gathered} y=-4x+c \\ y=-4 \\ x=8 \\ find\text{ c} \\ -4=-4(8)+c \\ -4=-32+c \end{gathered}[/tex][tex]c=28[/tex]Thus, the answer will be;
[tex]\begin{gathered} y=-4x+28 \\ y+4x=28 \end{gathered}[/tex]