we have the following:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]replacing:
17. (1, 0) and (5, 5)
[tex]m=\frac{5-0}{5-1}=\frac{5}{4}[/tex]therefore,
[tex]\begin{gathered} y=mx+b \\ y=\frac{5}{4}\cdot x-\frac{5}{4} \end{gathered}[/tex]19. (0, -1) and (3, -5)
[tex]m=\frac{-5-(-1)}{3-0}=\frac{-4}{3}=-\frac{4}{3}[/tex]therefore,
[tex]\begin{gathered} y=mx+b \\ y=-\frac{4}{3}\cdot x-1 \end{gathered}[/tex]21. (1, 9) and (6, 2)
[tex]m=\frac{2-9}{6-1}=\frac{-7}{5}=-\frac{7}{5}[/tex]therefore,
[tex]\begin{gathered} y=mx+b \\ y=-\frac{7}{5}\cdot x+10.4 \end{gathered}[/tex]