An electric field exerts force of 2.60 N on a 3.40 x 10-8 C charge. What is the magnitude of the electric field?Group of answer choices7.65 x 107 N/C8.43 x 107 N/C9.05 x 107 N/C12.0 x 107 N/C

Respuesta :

ANSWER

[tex]7.65\cdot10^7N\/C[/tex]

EXPLANATION

We want to find the magnitude of the electric field.

To do this, we have to apply the formula for electric field:

[tex]E=\frac{F}{q}[/tex]

where F = force exerted on the charged particle

q = electric charge on the particle

Hence, the magnitude of the electric field is:

[tex]\begin{gathered} E=\frac{2.60}{3.40\cdot10^{-8}} \\ E=7.65\cdot10^7N\/C \end{gathered}[/tex]

The correct answer is the first option.