Find the probability of randomly choosing three brown M&Ms in a row from a bag that contains 35 brown M&Ms out of 250 M&Ms total. Note that as you choose them, you immediately eat them.Question 4 options:0.08570.0120.420.00254

Respuesta :

We have to find the probability of each trial.

[tex]P_1=\frac{35}{250}[/tex]

In the first trial, we have 35 browns M&ms in total.

[tex]P_2=\frac{34}{249}[/tex]

Then, we have 34 browns and 249 in total because we ate one.

[tex]P_3=\frac{33}{248}[/tex]

We reduce again the events and the total outcomes because we ate another M&M.

Now, we have to multiply all of them

[tex]P=\frac{35}{250}\times\frac{34}{249}\times\frac{33}{248}=\frac{35\times34\times33}{250\times249\times248}=\frac{39,270}{15,438,000}=0.00254[/tex]

Hence, the last option is the correct answer.