The volume of the cylinder =
[tex]\Pi\cdot r^2\cdot h[/tex]
Where r is the radius of the base , h is the height , Pi = 3.14
So,
Given r = 2 mi , h = 5
so,
[tex]\text{volume}=\pi\cdot r^2\cdot h=3.14\cdot2^2\cdot5=3.14\cdot4\cdot5=62.8[/tex]
Rounding to the nearest whole number
so, the volume = 62.8 mi^3
the answer is option B) 63 mi^3
