we can use the Pythagorean theorem
where
[tex]c^2=a^2+b^2[/tex]
Let's try the theorem in all options
First option
[tex](\sqrt{13})^2=2^2+3^2[/tex][tex]13=4+9[/tex][tex]13=13[/tex]
since
the first option satisfies the Pythagorean theorem, Option A is a Right triangle
