A committee must be formed with 5 teachers and 3 students. If there are 8 teachers to choose from, and 10 students, how many different ways could the committee be made?

Respuesta :

Answer:

The committee could be made in 6,720 ways

Explanation:

Parameters:

• Total number of teachers avalable = 8

• Number of teachers to be chosen from this = 5

• Total number of students = 10

• Number of students to be chosen from this = 3

We have number of ways for each group to be:

Teachers:

[tex]\begin{gathered} 8C5=\frac{8!}{(8-5)!5!} \\ \\ =\frac{8!}{3!5!}=\frac{8\times7\times6}{3\times2\times1}=56 \end{gathered}[/tex]

Students:

[tex]\begin{gathered} 10C3=\frac{10!}{(10-3)!3!} \\ \\ =\frac{10!}{7!3!}=\frac{10\times9\times8}{3\times2\times1}=120 \end{gathered}[/tex]

Finally, the committee could be made in

[tex]120\times56=6,720ways[/tex]