The cost of "x" radios is $10x and transportaiton fee of $5. So cost equation for "x" radios is,
[tex]C(x)=10x+5[/tex](b)
The selling price of one radio is $12. So for "x" radio Profit(selling price) equation is,
[tex]S(x)=12x[/tex](c)
Determine the value of x for which profit equation is equal to cost equation.
[tex]\begin{gathered} 10x+5=12x \\ 2x=5 \\ x=\frac{5}{2} \end{gathered}[/tex]The number of radios can never be in fraction. So individual has to buy 3 radios to have equal cost and profit,.
