Respuesta :
Given inequality is:
[tex]4x+8y\leq-8[/tex]Now for (6,-4), Put x=6 nd y=-4 in given inequality:
[tex]\begin{gathered} 4(6)+8(-4)\leq-8 \\ 24-32\leq-8 \\ -8\leq-8 \end{gathered}[/tex]So for (6,-4) this inequality is true.
For (-2,-3) put x=-2 and y=-3 in given inequality:
[tex]\begin{gathered} 4(-2)+8(-3)\leq-8 \\ -8-24\leq-8 \\ -32\leq-8 \end{gathered}[/tex]As -32 is less than -8 then this condition is also true.
simillarly you can check for other options also.
For (-7,5) Put x=-7 and y=5 in given inequality:
[tex]\begin{gathered} 4(-7)+8(5)\leq-8 \\ -28+40\leq-8 \\ 12\leq-8 \end{gathered}[/tex]As 12 is grater than -8 so this condition is false.
And for (-6,0) put x=-6 and y=0 in given inequality:
[tex]\begin{gathered} 4(-6)+8(0)\leq-8 \\ -24\leq-8 \end{gathered}[/tex]As -24 is less than -8 so it is true.
