A model rocket is launched straight up. Its height in feet (y) above theground x seconds after launch is modeled by the quadratic function: y=-16x2 + 216x + 6.How many seconds did it take the rocket to reach its maximum height?

A model rocket is launched straight up Its height in feet y above theground x seconds after launch is modeled by the quadratic function y16x2 216x 6How many sec class=

Respuesta :

Given the Quadratic function:

[tex]y=-16x^2+216x+6[/tex]

You need to find the x-coordinate of the vertex of the parabola, in order to calculate how many seconds it took the rocket to reach its maximum height.

You can find the x-coordinate of the vertex of the parabola with the following formula:

[tex]x=-\frac{b}{2a}[/tex]

Knowing that a Quadratic function has this form:

[tex]y=ax^2+bx+c[/tex]

You can identify that, for this case:

[tex]\begin{gathered} a=-16 \\ b=216 \end{gathered}[/tex]

Substituting values into the formula, you get this result:

[tex]\begin{gathered} x=-\frac{216}{2(-16)} \\ x=6.75 \end{gathered}[/tex]

It took the rocket 6.75 seconds to reach its maximum height; so the answer is the Third option.