Respuesta :

[tex]\begin{gathered} (-51,\text{ -28) and (-10, 14)} \\ \text{slope for e}(M1)\text{: }\frac{y2-\text{ y1}}{x2\text{ -x1}} \\ \text{slope= }\frac{14--28}{-10--51}\text{ = }\frac{42}{41} \\ \text{for perpendicular: means M1}\times M2\text{ = -1} \\ \text{ }\frac{42}{41}\times\text{ M2 = -1} \\ \text{ 42M1 = -41 } \\ \text{ M1 = }\frac{-41}{42} \end{gathered}[/tex]

Otras preguntas