Given data
*The given force is F = 24 N
*The given angle with the horizontal is
[tex]\theta=79^0[/tex]
The formula for the vertical component of the force is pulling is given as
[tex]F_v=F\sin \theta[/tex]
Substitute the known values in the above expression as
[tex]\begin{gathered} F_v=24\times\sin 79^0 \\ =23.55\text{ N} \end{gathered}[/tex]
Hence, the vertical component of the force is pulling with is 23.55 N
