1) Write the atom-molecule ratio.
1 Fe: 1FeCl3
2) Moles of FeCl3 produced from Fe. Assuming that Fe is the limiting reactant.
2.1- Convert grams of Fe to moles of Fe.
The molar mass of Fe is 55.8450 g/mol
Sample: 311 g Fe
[tex]mol\text{ }Fe=311\text{ }g\text{ }Fe*\frac{1\text{ }mol\text{ }Fe}{55.8450\text{ }g\text{ }Fe}=5.57\text{ }mol\text{ }Fe[/tex]We have 5.57 mol Fe
2.2- FeCl3 produced.
5.57 mol Fe
1 Fe: 1FeCl3
[tex]mol\text{ }FeCl_3=5.57\text{ }mol\text{ }Fe*\frac{1\text{ }mol\text{ }FeCl_3}{1\text{ }mol\text{ }Fe}=5.57\text{ }mol\text{ }FeCl_3[/tex]5.57 mol FeCl3 would be produced from 311 g Fe. Assuming that Fe is the limiting reactant.
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