we have the expression
[tex]\frac{x^2+3x-4}{x+4}[/tex]
Remember that
The denominator can not be equal to zero
so
The value of x in the domain can not be equal to -4
we have that
[tex]x^2+3x-4=(x+4)(x-1)[/tex]
substitute
[tex]\frac{x^2+3x-4}{x+4}=\frac{(x+4)(x-1)}{(x+4)}=x-1[/tex]
answer is option D
