contestada

E. O 1.318 m/s²6. An object of mass 32 kg is being pulled on a friction lesshorizontal surface by means of two strings. One of the stringsis pulling forward, has a tension of 120 N and makesan angle of 30 degree with the horizontal-right. The other string ispulling backwards horizontally and has a tension of 10 N.Calculate the acceleration of the object. (1 point)A. 02.935 m/s²B.O2.506m/s2C. 05.172 m/sD. 03.816 m/s ²E. O4.308 m/s²

E O 1318 ms6 An object of mass 32 kg is being pulled on a friction lesshorizontal surface by means of two strings One of the stringsis pulling forward has a ten class=

Respuesta :

We first determine the total force ni he horizontal axis, that is:

[tex]\sum F_x=120cos(30)N-10N\Rightarrow\sum F_x=(60\sqrt{3}-10)N[/tex]

Now, we determine the acceleration:

[tex]\begin{gathered} (60\sqrt{3}-10)N=(32kg)a\Rightarrow a=\frac{(60\sqrt{3}-10)N}{32kg} \\ \\ \Rightarrow a=\frac{30\sqrt{3}-5}{16}m/s^2\Rightarrow a\approx2.935m/s^2 \end{gathered}[/tex]

So, the acceleration is approximately 2.935 m/s^2.

Otras preguntas