The value of y when x = 45 is 120
Here, we have a direct variation question
Let us have the constant of variation as k
Since it is a direct variation, the relationship between the two is;
[tex]y\text{ = kx}[/tex]
We can find the value of k from the initial values of x and y given
Mathematically, that would be;
[tex]k\text{ = }\frac{y}{x}\text{ = }\frac{8}{3}[/tex]
Now, we want to find the value of y when is 45
Recall;
[tex]\begin{gathered} y\text{ = kx} \\ \\ y\text{ = }\frac{8}{3}\text{ }\times\text{ 45} \\ \\ y=8\text{ }\times\text{ 15 = 120} \end{gathered}[/tex]