The potential difference is 2√5.
The energy stored in the capacitor can be calculated as follow:
U = 1/2 CV²
U = energy stored = 300J
C = capacitor = 30mf
V = potential difference
V= [tex]\sqrt{2U/ C}[/tex]
= [tex]\sqrt{2 (300) / 30}[/tex]
= [tex]\sqrt{2 * 10}[/tex]
= 2√5
Therefore the potential difference is 2√5.
To know more about the potential difference refer to the link given below:
https://brainly.com/question/24142403
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