(0.82 , 3.38) is estimate of the population mean weight loss for this diet in standard deviation.
What is standard deviation in math?
mean weight loss = 2.1lb
standard deviation = 4.8lb
sample size n = 40
std error = stdev/sqrt(n) = 4.8/sqrt(40) = 0.76
degrees of freedom = n - 1 = 39
critical value for alpha 0.10 and df 39 = +1.68
margin of error = critical value * std error = +1.68 * 0.76 = +1.28
confidence interval = sample mean + margin of error = 2.1 +1.28 = (0.82 , 3.38)
Yes it is effective since the values > 0mean weight loss = 2.1lb
standard deviation = 4.8lb
sample size n = 40
std error = stdev/sqrt(n) = 4.8/sqrt(40) = 0.76
degrees of freedom = n - 1 = 39
critical value for alpha 0.10 and df 39 = +1.68
margin of error = critical value * std error = +1.68 * 0.76 = +1.28
confidence interval = sample mean + margin of error = 2.1 +1.28 = (0.82 , 3.38)
Yes it is effective since the values > 0
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