Expression
[tex]\sqrt[]{72}=\sqrt[]{8\cdot9}=\sqrt[]{2^3\cdot3^2}[/tex]
Applying the exponent law
[tex]\sqrt[]{2^2\cdot2\cdot3^2}=\sqrt[]{2^2}\cdot\sqrt[]{2}\cdot\sqrt[]{3^2}[/tex]
Then
[tex]\begin{gathered} \sqrt[]{2^2}=2 \\ \text{and} \\ \sqrt[]{3^2}=3 \end{gathered}[/tex]
Therefore
[tex]2\cdot\sqrt[]{2}\cdot3[/tex]
Multiply 2 by 3
[tex]6\sqrt[]{2}[/tex]
Answer:
a = 6
b = 2
