11) In the first problem we have the angle with the ground and the hight of the truck so we can made a triangle in this form so:
So we can use the tg propertie to find the lenght of the truck so:
[tex]\begin{gathered} tg(30)=\frac{37.5}{h} \\ h=\frac{37.5}{0.577}\approx65 \end{gathered}[/tex]
So is 75 ft
12) in this problem the diagram is:
Now we can use the pythagorical theorem to find the distance between the first and the threth base so:
[tex]\begin{gathered} d=\sqrt[]{90^2+90^2} \\ d=\sqrt[]{8100+8100} \\ d=\sqrt[]{16200} \\ d=127.279 \end{gathered}[/tex]
Now to find the speed we can divide the distance by the time so:
[tex]s=\frac{127.279}{1.2}\approx106[/tex]
