Given the equation the equation :
[tex]3\cdot(2y-1)=9[/tex]Divide both sides by 3:
[tex]\begin{gathered} \frac{3(2y-1)}{3}=\frac{9}{3} \\ \\ 2y-1=3 \end{gathered}[/tex]Add 1 to both sides
[tex]\begin{gathered} 2y-1+1=3+1 \\ 2y=4 \end{gathered}[/tex]Divide both sides by 2:
[tex]\begin{gathered} \frac{2y}{2}=\frac{4}{2} \\ \\ y=2 \end{gathered}[/tex]So, the answer is y = 2
