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The results of the math exam showed that three eighths of the students made an “A” and one third of them made a “B”. In total, how many students took the exam if the remaining 14 students made a grade other than an “A” or “B”?

Respuesta :

3/8 = A

1/3 = B

So,

[tex]\frac{3}{8}+\frac{1}{3}=\frac{3(3)+1(8)}{8(3)}=\frac{9+8}{24}=\frac{17}{24}[/tex]

17/24 got A or B.

So, the remaining "part" is WHOLE (1) minus 17/24, which is:

1 - 17/24 = 7/24

This "7/24" is equal to 14 sstudents, we need to find the total, which can be labeled as "x".

Thus we can write a ratio and solve:

if 7/24 is 14, then 1 is x

[tex]\begin{gathered} \frac{\frac{7}{24}}{14}=\frac{1}{x} \\ \frac{7}{24}x=14 \\ x=\frac{14}{\frac{7}{24}} \\ x=14\cdot\frac{24}{7} \\ x=2\cdot24 \\ x=48 \end{gathered}[/tex]

Hence, total number of students is 48

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