We are given an equation;
[tex]4(x-3)=16[/tex]
From the question, it was said that her first step taken is;
To expand. we have;
[tex]4x-12=16[/tex]
Then her second step could be;
1. To add 12 to both sides.then we have;
[tex]4x-12+12=16+12[/tex]
2. To subtract -12 from both sides. then we have;
[tex]4x-12-(-12)=16-(-12)[/tex]
Both 1 and 2 are to eliminate the unlike term which is -12 from the right side of the equation.
3. Lastly, in a rare case we can first divide both sides by 4 or multiply both sides by 1/4, to reduce 4x to x. So we have;
[tex]\begin{gathered} \frac{1}{4}.(4x+12)=16.\frac{1}{4} \\ To\text{ have;} \\ x+3=4 \end{gathered}[/tex]
Therefore, 1,2 and 3 are correct
