Respuesta :

b.The slope is given m=-3 and coordinate is P(0,-4).

The equation determined is

[tex]y-y_1=m(x-x_1)[/tex][tex]y-(-4)=-3(x-0)[/tex][tex]y+4=-3x[/tex][tex]y=-3x-4[/tex]

d. The slope is given m=-1/2 and coordinate is (5,-2)

The equation obtained is

[tex]y-(-2)=-\frac{1}{2}(x-5)[/tex][tex]y+2=-\frac{1}{2}(x-5)[/tex][tex]y=-\frac{1}{2}x+\frac{5}{2}-2[/tex][tex]y=-\frac{1}{2}x+\frac{5-4}{2}[/tex][tex]y=-\frac{1}{2}x+\frac{1}{2}[/tex]

f. The slope is given m=2 and coordinate is P(1/2,3/4).

[tex]y-\frac{3}{4}=2(x-\frac{1}{2})[/tex][tex]y=2x-1+\frac{3}{4}[/tex][tex]y=2x-\frac{1}{4}[/tex]