Respuesta :

[tex]\frac{7x^2y^3}{28xy}[/tex]

Divide 7 by 28:

7/28 = 1/4

To divide the variables, subtract the exponents:

[tex]x^{(2-1)}y^{(3-1)}=x^1y^2=xy^2[/tex]

SO, the final expression is:

[tex]\frac{1}{4}xy^2=\frac{xy^2}{4}[/tex]

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