Given,
[tex]\begin{gathered} x-4y=1\ldots\ldots(1) \\ 2x-3y=3\ldots\text{.}\mathrm{}(2) \end{gathered}[/tex]
Multiply equation (1) by 2.
[tex]2x-8y=2\ldots\text{.}\mathrm{}(3)[/tex]
Solve equation (2) and (3)
[tex]\begin{gathered} 5y=1 \\ y=\frac{1}{5} \end{gathered}[/tex]
Put y = 1/5 in the equation (1)
[tex]\begin{gathered} x-4\times\frac{1}{5}=1 \\ x=1+\frac{4}{5} \\ x=\frac{9}{5} \end{gathered}[/tex]
Thus, the value of (x,y) will be (1/5,9/5).
Thus, the given point (9,2) is not the solution.
