Respuesta :

We know that

• The initial mass is 200 mg.

,

• The time is 4000 years.

,

• The half-life is 1590 years.

Let's use the half-life formula.

[tex]N(t)=N_o(0.5)^{\frac{t}{u_{}}}[/tex]

Using the given magnitudes, we have the following

[tex]N(4000)=200\cdot(0.5)^{\frac{4000}{1590}}\approx35mg[/tex]

Therefore, after 4000 years, there will remain 35 mg of Radium-226.

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