The initial expression is:
[tex]\frac{x-2}{3}+\frac{y+3}{4}=2[/tex]we can rewrite the function in the form:
[tex]y=mx+b[/tex]where m is the slope so:
[tex]\begin{gathered} \frac{y+3}{4}=-\frac{x-2}{3}+2 \\ \frac{y+3}{4}=-\frac{1}{3}x+\frac{2}{3}+2 \\ y+3=-\frac{4}{3}x+\frac{8\cdot4}{3} \\ y=-\frac{4}{3}x+10.6-3 \\ y=-\frac{4}{3}x+7.6 \end{gathered}[/tex]this means that the slope is -4/3 or -1.33
