I need help with so many questions it’s about 8th grade algebra it’s a packet please don’t bother helping me if you’re not willing to spend around 2 hours helping me

If two triangles are simiar, the corresponding sides are in proportion, so:
[tex]\begin{gathered} \frac{BC}{BA}=\frac{EF}{ED} \\ so\colon \\ \frac{12-6}{4-2}=\frac{27-15}{9-5} \\ \frac{6}{2}=\frac{12}{4} \\ 3=3 \end{gathered}[/tex]Answer:
D.