The formula for calculating margin of error is expressed as
[tex]\text{margin of error = z }\times\text{ (}\sqrt[]{\frac{pq}{n}})[/tex]
Where
p represents the probability of success
q represents the probability of failure
n represents sample size
z represents the z score for a 95% confidence interval
From the information given,
p = 30% = 30/100 = 0.3
q = 1 - p = 1 - 0.3 = 0.7
n = 4500
From the standard normal distribution table, z = 1.96
By substituting these values into the formula, we have
[tex]\text{margin of error = 1.96}\times\sqrt[]{\frac{0.3\times0.7}{4500}}\text{ = }0.013[/tex]
margin of error = 0.013
