Given the reaction:
[tex]CH_4+2O_2\to CO_2+2H_2O[/tex]We want to find the number of grams of CO2 produced from 79.7 grams of O2.
Using stoichiometry, we obtain:
[tex]79.7gO_2\cdot\frac{1molO_2}{32gO_2}\cdot\frac{1molCO_2^{}}{2molO_2}\cdot\frac{44gCO_2}{1molCO_2}=54.79gCO_2[/tex]Therefore, 54.79g of CO2 are produced.
