CHUA AI || || ||de| Ve 1 C Campus Student * + gle.com document/d/17CMSiwezsegtHsyOblHopstmerahOHU T52095mk/edit # 1 o for Stud Henry R3 'The Fight As I Semester 1 Assess Classmate answers https://www.youtu. Yao Rice w udent Version Constructed Response Question: Format Tools Add-ons Help Accessibility Last edit was 2 days ago Normal text BI YA OD EEE EEE 4 it will Constructed Response Question: Part A: What could be the value of B that would make the relation{(B.1) (2,3) (4,5)} a function? Explain how you know. Part B: Using the same ordered pairs, what could be the value of B that would create a relation only? Explain how you know. Please include vocabulary terms: input, output, relation, function of B that would make the relation

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Answer

Part A

The values of B that can make the pairing a function include any other real number apart from the other input variables 2 and 4.

(B, 1), (2, 3), (4, 5)

Input variables = B, 2 and 4

Output variables = 1, 3 and 5

For this relation to be a function,

B = Any other number apart from 2 and 4.

A function table will have the input variable characterized by x and the output variable characterized by f(x)

x | f(x)

B | 1

2 | 3

4 | 5

B = Any other number apart from 2 and 4.

Part B

B can take on any real number value as the input variable in order for this to still be a relation.

Explanation

Restating the question as a statement

The question first asks us to find the value of B in the relations given as (B, 1), (2, 3) (4, 5) that makes this relation a function.

Answer the question

To answer the question, we need to first note what a function is.

A function is a pairing/relation that takes up each value of an input variable and gives a corresponding value of an output variable without the same values of the input variable giving different values of the output variable.

So, basically, a given input term in the pairing cannot have two different output answers.

So, in order for the pairing given [(B, 1), (2, 3), (4, 5)] to be termed a function, the value of B cannot take on the values of the other input variable (2 and 4). So, the values of B that can make the pairing a function is any other real number apart from 2 and 4.

(B, 1), (2, 3), (4, 5)

Input variables = B, 2 and 4

Output variables = 1, 3 and 5

For this relation to be a function,

B = Any other number apart from 2 and 4.

A function table will have the input variable characterized by x and the output variable characterized by f(x)

x | f(x)

B | 1

2 | 3

4 | 5

B = Any other number apart from 2 and 4.

For Part B, any input value for B will make this a relation. A relation doesn't have the strict rules that limit what is termed a function.

So, for this question, B can take on any real number value as the input variable in order for this to still be a relation.

Check the answer

To check the answer, we will just put values in place of B and show that the relation is a function or not.

(B, 1), (2, 3), (4, 5)

If B = 2 or 4, it's not a function

(2, 1), (2, 3), (4, 5) (Not a function)

(4, 1), (2, 3), (4, 5) (Not a function)

But if B = Any other number apart from 2 and 4.

(1, 1), (2, 3), (4, 5) (This is a function)

(10, 1), (2, 3), (4, 5) (this is a function)

This adequately helps us to check our answer.

Explaining your reasoning

Look throught the answer session, All of the explanation required have been provided there.

Hope this Helps!!!