In Mr. Lowery's mathematics class, 6/8 of the students received A's and 1/8 received B's. What fraction of the students received either A's or B's?

ANSWER
[tex]\frac{7}{8}[/tex]EXPLANATION
Given:
[tex]\begin{gathered} A=\frac{6}{8} \\ B=\frac{1}{8} \end{gathered}[/tex]Fraction of A or B
[tex]\begin{gathered} A+B=\frac{6}{8}+\frac{1}{8} \\ take\text{ the LCM} \\ =\frac{6+1}{8} \\ =\frac{7}{8} \end{gathered}[/tex]Hence, the fraction of the students received either A's or B's is 7/8.