f(x) = { -x^2 + 3 if x <= 35 - 10x + 28 if x > 5
Let f be the function defined above. Which of the following statements about fis true? a. S is continuous and differentiable at x = 5. b. fis continuous but not differentiable at x = 5. c. f is differentiable but not continuous at x = 5. d. ſis defined but neither continuous nor differentiable at x = 5.

Respuesta :

The correct answer is option (a) f is continuous and differentiable at x = 5

A function is differentiable at a point if left hand limit = right hand limit at that point.

f(5) = -22 on solving

left hand limit (LHL) = [tex]lim_{x- > 5^{-} }[/tex] (f(x) - f(5)) / x - 5 = [tex]lim_{x- > 5^{-} }[/tex] (-x² + 3 + 22 ) / ( x - 5)  = [tex]lim_{x- > 5^{-} }[/tex] (- ( x² + 25))/ (x- 5) = [tex]lim_{x- > 5^{-} }[/tex] (- (x-5)(x + 5)) / (x-5) = [tex]lim_{x- > 5^{-} }[/tex] (-(x+5) = - 10      (putting x = 5)

Right hand limit (RHL) = [tex]lim_{x- > 5 }[/tex] (f(x) - f(5) )/ ( x - 5) = [tex]lim_{x- > 5 }[/tex] (-10x + 28 + 22) / (x - 5) = [tex]lim_{x- > 5 }[/tex] ( - 10x + 50 )/ ( x - 5 ) = [tex]lim_{x- > 5 }[/tex] ( - 10 ( x - 5)) / (x-5 ) = -10

Thus on solving we see that LHL = RHL =-10  at the point 5

Therefore the function is differentiable at point 5

Also for the point say c = 5 , f(c) = -22 that is f(c) exists. The limit [tex]lim_{x- > 5 }[/tex] f(x) = - 22 and  [tex]lim_{x- > 5^{-} }[/tex] f(x) = -22. As both the limits are equal so the limit exists. But we see that the limit of the function as x approaches c and the value of f(c) are equal. Thus the function is continuous.

Thus the correct answer to the question is option (a) that is f is continuous and differentiable at x = 5

What is a continuous function :

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