Observe from the graph that the parabola intersects the x-axis at x=-2 and x=-3.
So -2 and -3 will be the zeroes of the quadratic polynomial.
It means that (x+2) and (x+3) must be the factors of the quadratic polynomial,
So the quadratic equation can be formed as,
[tex]\begin{gathered} y=(x+2)(x+3) \\ y=x(x+3)+2(x+3) \\ y=x^2+3x+2x+6 \\ y=x^2+5x+6 \end{gathered}[/tex]
Therefore, option A is the correct choice.
