Given that ABC is a right angle triangle And AC=4 and BC=10
So according to pythgoreous theorem:
[tex]AB^2+AC^2=BC^2[/tex]
Now put the values in it:
[tex]\begin{gathered} AB^2+(4)^2=(10)^2 \\ AB^2+16=100 \\ AB^2=100-16 \\ AB^2=84 \\ AB=\sqrt[]{84} \\ AB=\sqrt[]{4\times21} \\ AB=2\sqrt[]{21} \end{gathered}[/tex]
Hence the correct option is B.
