Answer:
[tex]\text{ He will drive }3\frac{15}{16}\text{ fewer miles on Friday than on Tuesday.}[/tex]
Step-by-step explanation:
We can see that Mr. Conners is descending the miles he drove, let's see if it is a constant descending:
[tex]\begin{gathered} 71\frac{7}{16}-70\frac{1}{8}=\frac{21}{16} \\ 70\frac{1}{8}-68\frac{13}{16}=\frac{21}{16} \end{gathered}[/tex]
It means he is driving 21/16 miles less on each day, then for Thursday:
[tex]\begin{gathered} 68\frac{13}{16}-\frac{21}{16}=\frac{135}{2}\text{ Thursday} \\ \frac{135}{2}-\frac{21}{16}=\frac{1059}{16}\text{ Friday} \\ \text{Subtract friday by tuesday to se}e\text{ how many fewer miles he will drive:} \\ \frac{1059}{16}-70\frac{1}{8}=\frac{63}{16} \\ \text{Fraction to mixed number:} \\ \frac{63}{16}=3\frac{15}{16} \end{gathered}[/tex]
