Using pythagorean theorem:
[tex]c^2=a^2+b^2[/tex]Solve for b:
[tex]\begin{gathered} c^2=(49b)^2+b^2 \\ c^2=2401b^2+b^2 \\ 3721=2402b^2 \\ b^2=\frac{3721}{2402} \\ b=\sqrt[]{\frac{3721}{2402}} \\ b\approx1.2446 \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} a=49(1.2446) \\ a\approx60.9873 \end{gathered}[/tex]
