If 6.95 mol of ethane (C2H6) undergo combustion according to the unbalanced equation C2H6 + O2 ——- CO2 + H2OHow many moles of O2 is required? Answer in units of mol.

Answer
24.325 mol
Explanation
The unbalanced equation is:
C₂H₆ + O₂ → CO₂ + H₂O
The balanced equation will be:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Given mole of ethane = 6.95 mol
From the balanced equation:
2 mol of C₂H₆ is required by 7 mol of O₂
Therefore, 6.95 mol of C₂H₆wills requir:
[tex]\frac{6.95\text{ mol }C_2H_6\times7\text{ mol }O_{2}}{2\text{ mol }C_2H_6}=24.325\text{ mol of }O_{2}[/tex]Hence, 24.325 mol of O2 is required.