The work done by a gas at contant pressure is given by:
[tex]\begin{gathered} W=F\times d \\ P=\frac{F}{A}\therefore F=P\times A \\ \\ W=P\times A\times d\text{ }But,\text{ }A\times d=V \\ W=P\Delta V \\ P:pressure(Pa)1atm=101325Pa \\ F:force \\ A:area \\ V:volume(m^3)=\frac{L}{1000}=m^3 \\ d:distance \\ W:workdone \\ \Delta V:(V_f-V_i) \\ \end{gathered}[/tex]By substituting the known values in the equation we have:
[tex]\begin{gathered} W=303975\text{ }Nm^{-2}\times(0.025m^3-0.005m^3) \\ W=6079.5Nm \\ \\ W=6,079.5J \end{gathered}[/tex]Answer: Work done is +6,079.5J.
