The question is given to be:
[tex]\frac{x^2+3y}{xy}[/tex]
Given the following values:
[tex]\begin{gathered} x=4 \\ y=2 \end{gathered}[/tex]
Substitute the values into the expression:
[tex]\Rightarrow\frac{4^2+3(2)}{4\times2}[/tex]
Solving, we have:
[tex]\Rightarrow\frac{16+6}{8}=\frac{22}{8}=\frac{11}{4}=2\frac{3}{4}[/tex]
The correct answer is OPTION D.
