To solve this expression, we can proceed as follows:
[tex]\frac{y}{3}+\frac{8y}{4}-\frac{3}{6}=y+\frac{7}{2}[/tex]
We can find the least common multiple of (3, 4, and 6). It is 12, to have a common fraction in the first member of the equation.
[tex]\frac{4y+24y-6}{12}=y+\frac{7}{2}\Rightarrow4y+24y-6=12\cdot(y+\frac{7}{2})[/tex]
Then, adding the like terms:
[tex]28y-6=12y+42\Rightarrow28y-12y=42+6\Rightarrow16y=48\Rightarrow y=\frac{48}{16}\Rightarrow y=3[/tex]
Then, the value for y = 3 (First option).
