The flag pole is a cylinder, the surface area of the cylinder is given by:
[tex]SA=2\pi r^2+2\pi rh[/tex]
Where:
[tex]\begin{gathered} r=\frac{d}{2}=\frac{0.003}{2}=0.0015m \\ h=16m \end{gathered}[/tex]
Therefore:
[tex]\begin{gathered} SA=2\pi\cdot(0.0015)^2+2\pi(0.0015)(16) \\ SA\approx0.2m^2 \end{gathered}[/tex]
Answer:
0.2 m²
