Given:
[tex]f(x)=(x-5)^2+1[/tex]
Required:
To complete the function table for the given points and to graph the function.
Explanation:
Consider the given function
[tex]f(x)=(x-5)^2+1[/tex]
When x= 2
[tex]\begin{gathered} f(x)=(2-5)^2+1 \\ =(-3)^2+1 \\ =9+1 \\ =10 \end{gathered}[/tex]
When x = 3,
[tex]\begin{gathered} f(x)=(3-5)^2+1 \\ =2^2+1 \\ =4+1 \\ =5 \end{gathered}[/tex]
When x =4,
[tex]\begin{gathered} f(x)=(4-5)^2+1 \\ =1+1 \\ =2 \end{gathered}[/tex]
When x= 5,
[tex]\begin{gathered} f(x)=(5-5)^2+1 \\ =1 \end{gathered}[/tex]
When x = 6,
[tex]\begin{gathered} f(x)=(6-5)^2+1 \\ =1+1 \\ =2 \end{gathered}[/tex]
Now the graph of the function is,
Final Answer:
The graph of the function is
